(x^-2y^5)^1/2/y^-7/4x^5

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Solution for (x^-2y^5)^1/2/y^-7/4x^5 equation: 


D( x )

y^-7 = 0

x = 0

y^-7 = 0

y^-7 = 0

y^-7 = 0

x naleu017Cy do R

x = 0

x = 0

x belongs to the empty set

x^5*(((((x^-2*y^5)^1)/2)/(y^-7))/4) = 0

x belongs to the empty set

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